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X^2-47X-630=0
a = 1; b = -47; c = -630;
Δ = b2-4ac
Δ = -472-4·1·(-630)
Δ = 4729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{4729}}{2*1}=\frac{47-\sqrt{4729}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{4729}}{2*1}=\frac{47+\sqrt{4729}}{2} $
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